Moller device
The device, designed by Colonel (later General) G.
L. Moller, commander of the Vilna artillery firing range, and tested for a
long time at the Officers’ Artillery School in Tsarskoe Selo, was not officially adopted by the Russian Army, but
it was used by the Bulgarian fortress-siege artillery between the end of the
19th and the beginning of the 20th century. |
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The device consisted of
two separate binoculars, which could be used
separately, or together, as a common instrument. Both binoculars have the
same device. On one of the lenses of
the eyepiece tube of both binoculars was engraved a horizontal scale of
divisions composed of 5 long vertical lines and 5 short vertical lines to the
left and the same number to the right, relative to a long vertical line
passing through the centre. The long central line was marked with 0, while
the long lines to the left and right with the numbers 2, 4, 6, etc. Another
unnumbered long line was engraved in the middle of
the lens perpendicular to the above lines. The
lenses of the other eyepiece tubes were transparent and without graduations;
they served only to help one see the observed object more clearly. |
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The size of the
engraved divisions was such that the angular unit of a division (between a
short line and a long line) corresponded to 6’, that is, the angle formed by joining
the edges of a division to the centre of the eyepiece was equal to 6’
minutes. The distance between the extreme divisions was 2°. The two binoculars were placed on a tripod stand, which
allows them to be rotated horizontally and vertically. Use of the Moller
device The Moller device could
be used : a)
to determine the lateral
deflection of the projectile,
using the binoculars separately. The binoculars, placed on the tripod support
firmly planted in the ground, were positioned in
plain sight and in a horizontal position, so that the scale marks occupied a
vertical position. By acting on the tripod screws, the long vertical line
marked with 0 was directed towards the objective,
and the other unnumbered line, which in that position had a horizontal direction,
was also referred to that point. During the shot, the
observer only had to see against which division of the scale the projectile
had burst to determine with a simple formula how many meters the projectile
on the left or right deflected from the point where the observation was carried out. Knowing that the circle
arch that underlies an angle of 1’ is equal to 0.0003 of the radius with
which the arch is described and that the arch corresponding to a division of
the device (6’) is 6 times greater, since the length D is the extent of the processes of the projectile included in a
division, and R is the distance
from the target, it is easy to determine D
when knowing R. For example,
if the distance from the target is 2200 m, the value of a division of the device
is D = 0.0003 x 2200 x 6 = 3.96 = 4
m, when the projectile is seen below 5 divisions,
its derivation in meters is 4 x 5 = 20 m. b)
To determine the height of the dispersion of
the shrapnel, using both binoculars
together. In this case, the observer proceeded as above, with the difference,
that the binoculars were placed one under the other,
so the marks of the scale were horizontal and the long numbered line with 0
was directed to the line or to the point with respect to which the height of
dispersions is calculated. c)
To determine the width of the target, if the distance from it is
known, or vice versa, and to
determine the depth of the target, if the distance from it is known,
using the binoculars separately. The observer determines how many tools of
the device cover the target, for example 4 divisions. For the first case, we
have: D = 0.0003 R d
or R = D/0.0003 d, where d
indicates the divisions of the device in which the target is enclosed,
expressed in minutes. So, if the target width is 40 m, R = 40/0.0003 x 24 = 5.555 m. For the second case, if the
distance is known and equal to 5.555 m, we have: D = 0.0003 R d or D = 0.0003 x 5.555 x
24 = 40 m. d)
To determine the deflection of the
projectile in the distance,
placing the two binoculars one on the right and the other on the left of the
battery. When shooting great distances, the base (the distance between the
two tripods) should not be less than 200 m. The two binoculars were aimed so
that the long lines numbered 0 on the scale, taking
a vertical position, point to the same point on the target, using an
auxiliary point. When the shot is fired, the two observers noted against
which division of the scale the projectile had fallen and whether it was to
the left or right of the line numbered with 0. If an observer noticed the dispersion of the projectile on the
side of the zero line, from which his own battery was located (for the
observer on the right from the left and for the one on the left from the
right), he reported the number of divisions under which he had observed the
fall, with the sign –, if he had noticed it on the opposite side, he reported
it with the sign +. The algebraic sum of
the data from the two devices gave the numerical value of the long or short
projectile burst. For example, if one observer gives a reading of –4 and the other +7, their algebraic sum is –4 +7 = +3,
indicating that the projectile is falling behind the target. Knowing this
data (+3) and the value of one division of the device in meters for the given
position, through a conversion formula the observers could determine how many
meters the projectile had fallen behind the target. The
value of a division of the device should also be determined in minutes of the
elevation angle or in graduations of the sight, to establish by how much the
elevation of the gun had to be increased, to move
the trajectory forward or backward according with the determined value in
meters of a division of the device. These values could be determined in
advance by calculation, or obtained directly from the results of the first
two shots. In
this second case, after each of the two shots, the observers noted the
readings of their devices (algebraic sum) : the difference in the sight
heights or in the elevation angle for the first and second shots divided by the
numerical (arithmetic) sum of the readings of the devices for these two shots
gives the value of a division, in sight graduation or in minutes, from which
the corresponding value in meters is easily obtained. For example,
shooting with a 15cm L/30 cannon at a distance of 3900 m, the indications of
the devices gives : –4 for a sight height of 110
graduations, +8 for a sight height of 118 graduations. Knowing that at this
distance a sight graduation varies the distance by 24 m, with a difference in
the elevation heights of 8 graduations, we obtain: 8x24=192 m. Since the sum
of the readings of the devices is 8+4=12, each unit of the readings of the
devices corresponds to 192/12 = 16 m. e)
To determine the interval of dispersion of
the shrapnel bursts, the observer proceed
as above. |
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SOURCES : - Ръководство за занятията въкреспостата артилерия. Част IV. Подготовка и служба на наблюдателите,
Sofia 1902, pp. 26-32; - FRAENKEL.
J. : “Cours pratique de tir à l’École des officiers de l’artillerie
russe en 1884 et 1885” : Revue d’Artillerie XXIX (Octobre 1886 –
Mars 1887), pp. 264-265. |